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- #1

maani

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Hi I have computed a cross section to 10^{-6} GeV^{2}. Now I have to convert it to barn, but don't know how. Can anybody help me? Is it ok to have a cross section in units of GeV^{2} or is my result completely wrong?

Thanks!

## Answers and Replies

- #2

Vanadium 50

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You made a mistake somewhere. It should be 1/GeV^{2}.

The conversion factor you need is [itex]\hbar c[/itex] = 200 MeV fm.

- #3

humanino

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Vanadium 50 said:

[itex]\hbar c[/itex] = 200 MeV fm.

Equivalently, [itex]\left(\hbar c\right)^{2}=0.389\text{ GeV}^2\text{mbarn}[/itex]

- #4

Count Iblis

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If you're doing quantum gravity, then:

GeV^2 = 1.752*10^(-80) barn

- #5

humanino

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Count Iblis said:

If you're doing quantum gravity, then:

See AlsoThe Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!)What Is a Competitive Analysis? Definition + Template (2022)Barbados International Travel InformationJob Opportunities in Germany after Graduation - Working Visa Guide | CBSGeV^2 = 1.752*10^(-80) barn

It seems to me confusing in the context of the original question to hide [itex]\hbar[/itex] and *c*. Vanadium 50's and my result are on the first page of the particle data group booklet or review, so I think we were justified not to give further details (unless requested). I'd like to request a clarification about your formula. It seems to me, energy and length have inverse dimension for instance. Can you please re-establish the proper [itex]\hbar[/itex], *c* and (probably) *G* factors ?

- #6

Count Iblis

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humanino said:

It seems to me confusing in the context of the original question to hide [itex]\hbar[/itex] and

c. Vanadium 50's and my result are on the first page of the particle data group booklet or review, so I think we were justified not to give further details (unless requested). I'd like to request a clarification about your formula. It seems to me, energy and length have inverse dimension for instance. Can you please re-establish the proper [itex]\hbar[/itex],cand (probably)Gfactors ?

Well, I agree that the OP really meant GeV^(-2) and agree with your answers. Now, if you put G = 1, then of course, any power of GeV could be a cross section (because you've made physics dimensionless).

Now, I don't work in particle physics so, I don't have the conversion factors in my head. So, what I always do is use a few well known formulae that contain hbar, c and G to do the conversion.

To convert GeV^2 to a cross section, you can use that in General Relativity, mass and length have the same dimensions (if you put c = G = 1). So, GeV^2 is already a cross section and no additional conversion using hbar needs to be performed.

To restore G and c, we just hijack the formula for gravitational potential energy, so:

m^2 G/r = energy = m c^2

this is a dimensionally correct expression, that doesn't need to make sense. So, we have:

m G/(c^2 r) = dimensionless

Or:

E G/(c^4) = length

where E is an energy. So, we see that:

cross section = E^2 G^2/c^8

If you know the formulas for Planck length, Planck energy etc. etc., you can do the conversion directly. To convert GeV^n to a cross section, you simply divide this by the Planck energy to the power n and multiply by the Planck length squared.

- #7

Vanadium 50

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I think this is singularly unhelpful.

We have someone who is doing their first calculation - we know this, because they are having unit problems. Suggesting they start popping Planck masses in until the units come out right is not going to help them get the right answer. It's simply the wrong thing to do.

- #8

maani

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Thanks to all of you for the fast answers. This was really my first computation and it was completely wrong. I am still working on it. But i have learned at least how to convert the units.

- #9

Vanadium 50

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It's very smart to carry along the units, at least until you gain more facility with these calculations. People will say, "who cares if you drop an hbar or a c", but I would respond, "but who knows what else you dropped?" Then later when you get more experience, taking the shortcut becomes more reasonable.

- #10

Count Iblis

Vanadium 50 said:

I think this is singularly unhelpful.

We have someone who is doing their first calculation - we know this, because they are having unit problems. Suggesting they start popping Planck masses in until the units come out right is not going to help them get the right answer. It's simply the wrong thing to do.

It is very unhelpful to keep students indoctrinated in the wrongful use of units. Students learn units the wrong way in high school and even at university, the false myth of the meaning of units is promoted, to the detriment of science. Then what you see is that advanced university level students are struggeling with what should be a trivial high school physics exercise.

Even many professional physicisist do not understand units as

http://arxiv.org/abs/hep-th/0208093" [Broken].

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- #11

Count Iblis

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Vanadium 50 said:

It's very smart to carry along the units, at least until you gain more facility with these calculations. People will say, "who cares if you drop an hbar or a c", but I would respond, "but who knows what else you dropped?" Then later when you get more experience, taking the shortcut becomes more reasonable.

It's not just a shortcut, natural units are a bona fide unit system. The conversion back to SI units is very simple. With some minor practice, the chances of making mistakes are much less likely if you use natural units than if you use SI units.

The constants c, hbar, G, k_b, etc. etc. are nothing more than irrelevant conversion factor. Then, if we intend to use SI units when actually inserting numbers in the equation, we should make sure the correct conversion factors are present in the final result. But it can be extremely cumbersome to derive the equation with the conversion factors already present in the intermediary steps.

It is a bit like the complicated formulas frequently used by engineers were e.g. pressure appears in different ways, e.g. in atmospheres and in mm Hg. Then the formula also contains a conversion factor which has exactly the same interpretation as c, hbar, G, k_b etc.

- #12

humanino

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Count Iblis said:

It is a bit like the complicated formulas frequently used by engineers were e.g. pressure appears in different ways, e.g. in atmospheres and in mm Hg.

Not really. Keeping track of the powers of mass is quite a useful consistency check. I'd say it helps to avoid errors. Anyway, unless the original posters intends to go into quantum gravity, in which case this is not the appropriate sub-forum, advising him to overlook all dimensions together is certainly not very pedagogical. First he should learn the dimensions of the various fields, like spinors/vectors etc... at the very least.

- #13

Count Iblis

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Yes, I agree that it's useful to keep track of the powers of the mass. But then you can put hbar = c = 1. The fact that inverse mass is a length should be common knowledge. Even I know that and I don't work with this stuff on a daily basis.

- #14

humanino

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Count Iblis said:

Yes, I agree that it's useful to keep track of the powers of the mass. But then you can put hbar = c = 1. The fact that inverse mass is a length should be common knowledge. Even I know that and I don't work with this stuff on a daily basis.

When I said power, I meant both positive and negative. That's indeed what we do all the time. The problem comes about with m^2 G/r=E and setting G=1. With an arbitrary number of hidden G factors, you loose the ability to check the number of powers of mass (or energy, or length, or time) on both sides of the equation. For instance, with

cross section = 1/(E^2)

- #15

Count Iblis

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humanino said:

When I said power, I meant both positive and negative. That's indeed what we do all the time. The problem comes about with m^2 G/r=E and setting G=1. With an arbitrary number of hidden G factors, you loose the ability to check the number of powers of mass (or energy, or length, or time) on both sides of the equation. For instance, with

cross section = 1/(E^2)

Indeed, but then, you're not going to set G = 1 in ordinary QFT computations. And if one contemplates a fundamental theory, then one has to be reasonble and accept the fact that Nature may be fundamentally dimensionless.

If you formulate some lattice statistical mechanics model, like the Ising model, you only have pure numbers. But close to the critical temperature you can look at some scaling limit in which you can formulate hte model as some effective field theory. The correlation length then enters the effective theory as an inverse mass.

Cardy writes in one of his books that the Renormalization Group is simply a sophisticated way of doing dimensional analysis.

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## FAQs

### What number is represented by barn? ›

A barn (symbol: b) is a metric unit of area equal to **10 ^{−}^{28} m^{2}** (100 fm

^{2}).

**What is a barn measurement? ›**

barn, unit of area used to measure the reaction cross section (generally different from the geometric cross section) of atomic nuclei and subatomic particles in the study of their interactions with other nuclei or particles. It is equal to 10^{−}^{24} square cm.

**How do you convert to natural units? ›**

**To convert natural unit → SI,** **multiply by factor**. To convert SI → natural unit, divide by factor. For SI units of (kgα mβ sγ), natural units are Eα−β−γ.

**What is barn used for? ›**

barn, in agriculture, farm building for **sheltering animals, their feed and other supplies, farm machinery, and farm products**. Barns are named according to their purpose, as hog barns, dairy barns, tobacco barns, and tractor barns.

**Is barn unit of distance? ›**

Angstrom, fermi and parsec are the units of length whereas **barn is the unit of nuclear cross-section**.